What are the solutions to the equation 2x^2-5=-9x ?

The solutions to the equation 2x^2-5=-9x are x= 1/2 ,x=-5

Find the zeros of 2x^2-5=-9x

The zeros of 2x^2-5=-9x are x= 1/2 ,x=-5

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2 x^{2} - 5 = - 9 x

x = \frac{1}{2}, x = - 5

Decimal Notation

x = 0.5, x = - 5

Solution steps

2 x^{2} - 5 = - 9 x

Move

9 x

to the left side

2 x^{2} - 5 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 9 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 5) = 11

x_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 11}{2 \cdot 2}, x_{2} = \frac{- 9 - 11}{2 \cdot 2}

x = \frac{- 9 + 11}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 9 - 11}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 5

x, x^{2} + x y + y^{2} - 4 = 0

2 y^{2} + 7 y - 4 = 0

x^{2} - 4 b = 0

2 t^{2} - 8 t = - 3

3 x^{2} - 18 x + 1

What are the solutions to the equation 2x^2-5=-9x ?
The solutions to the equation 2x^2-5=-9x are x= 1/2 ,x=-5
Find the zeros of 2x^2-5=-9x
The zeros of 2x^2-5=-9x are x= 1/2 ,x=-5