What are the solutions to the equation 9x^2+24x+17=0 ?

The solutions to the equation 9x^2+24x+17=0 are x=-4/3+i 1/3 ,x=-4/3-i 1/3

Find the zeros of 9x^2+24x+17=0

The zeros of 9x^2+24x+17=0 are x=-4/3+i 1/3 ,x=-4/3-i 1/3

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9 x^{2} + 24 x + 17 = 0

x = - \frac{4}{3} + i \frac{1}{3}, x = - \frac{4}{3} - i \frac{1}{3}

Solution steps

9 x^{2} + 24 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 17}{2 \cdot 9}

Simplify

2 4^{2} - 4 \cdot 9 \cdot 17 : 6 i

x_{1, 2} = \frac{- 24 \pm 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 24 + 6 i}{2 \cdot 9}, x_{2} = \frac{- 24 - 6 i}{2 \cdot 9}

x = \frac{- 24 + 6 i}{2 \cdot 9} : - \frac{4}{3} + i \frac{1}{3}

x = \frac{- 24 - 6 i}{2 \cdot 9} : - \frac{4}{3} - i \frac{1}{3}

The solutions to the quadratic equation are:

x = - \frac{4}{3} + i \frac{1}{3}, x = - \frac{4}{3} - i \frac{1}{3}

6 (x^{2} - 2) = 3 (x^{2} + 1)

x (x + 2) = 120

x, \frac{x ^{2}}{18} = r

s^{2} + 2 s + 20 = 0

y^{2} + 2 y + 5 y = 5 y^{2} - 4 y

What are the solutions to the equation 9x^2+24x+17=0 ?
The solutions to the equation 9x^2+24x+17=0 are x=-4/3+i 1/3 ,x=-4/3-i 1/3
Find the zeros of 9x^2+24x+17=0
The zeros of 9x^2+24x+17=0 are x=-4/3+i 1/3 ,x=-4/3-i 1/3