What are the solutions to the equation 112x^2-56x+3=0 ?

The solutions to the equation 112x^2-56x+3=0 are x=(7+2sqrt(7))/(28),x=(7-2sqrt(7))/(28)

Find the zeros of 112x^2-56x+3=0

The zeros of 112x^2-56x+3=0 are x=(7+2sqrt(7))/(28),x=(7-2sqrt(7))/(28)

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112 x^{2} - 56 x + 3 = 0

x = \frac{7 + 2 7}{28}, x = \frac{7 - 2 7}{28}

Decimal Notation

x = 0.43898 \dots, x = 0.06101 \dots

Solution steps

112 x^{2} - 56 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 56 ) \pm ( - 56 ) ^{2} - 4 \cdot 112 \cdot 3}{2 \cdot 112}

(- 56)^{2} - 4 \cdot 112 \cdot 3 = 167

x_{1, 2} = \frac{- ( - 56 ) \pm 16 7}{2 \cdot 112}

Separate the solutions

x_{1} = \frac{- ( - 56 ) + 16 7}{2 \cdot 112}, x_{2} = \frac{- ( - 56 ) - 16 7}{2 \cdot 112}

x = \frac{- ( - 56 ) + 16 7}{2 \cdot 112} : \frac{7 + 2 7}{28}

x = \frac{- ( - 56 ) - 16 7}{2 \cdot 112} : \frac{7 - 2 7}{28}

The solutions to the quadratic equation are:

x = \frac{7 + 2 7}{28}, x = \frac{7 - 2 7}{28}

(k - 1) y^{2} - 5 y + 3 k - 7 = 0

x^{2} + 4 x - 45 = 0

- 2 x^{2} - 6 x + 7 = 0

2 u^{2} - 5 u - 3 = 0

x, y = - 0.02 x^{2} + x + 2.6

What are the solutions to the equation 112x^2-56x+3=0 ?
The solutions to the equation 112x^2-56x+3=0 are x=(7+2sqrt(7))/(28),x=(7-2sqrt(7))/(28)
Find the zeros of 112x^2-56x+3=0
The zeros of 112x^2-56x+3=0 are x=(7+2sqrt(7))/(28),x=(7-2sqrt(7))/(28)