What are the solutions to the equation -2x^2-6x+7=0 ?

The solutions to the equation -2x^2-6x+7=0 are x=-(3+sqrt(23))/2 ,x=(sqrt(23)-3)/2

Find the zeros of -2x^2-6x+7=0

The zeros of -2x^2-6x+7=0 are x=-(3+sqrt(23))/2 ,x=(sqrt(23)-3)/2

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- 2 x^{2} - 6 x + 7 = 0

x = - \frac{3 + 23}{2}, x = \frac{23 - 3}{2}

Decimal Notation

x = - 3.89791 \dots, x = 0.89791 \dots

Solution steps

- 2 x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

(- 6)^{2} - 4 (- 2) \cdot 7 = 223

x_{1, 2} = \frac{- ( - 6 ) \pm 2 23}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 23}{2 ( - 2 )}, x_{2} = \frac{- ( - 6 ) - 2 23}{2 ( - 2 )}

x = \frac{- ( - 6 ) + 2 23}{2 ( - 2 )} : - \frac{3 + 23}{2}

x = \frac{- ( - 6 ) - 2 23}{2 ( - 2 )} : \frac{23 - 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 23}{2}, x = \frac{23 - 3}{2}

2 u^{2} - 5 u - 3 = 0

x, y = - 0.02 x^{2} + x + 2.6

4 x (x - 2) + 3 (x - 3) = - 3

x, y^{4} = (x + 2)^{2}

4 z^{2} - 19 z + 18 = 0

What are the solutions to the equation -2x^2-6x+7=0 ?
The solutions to the equation -2x^2-6x+7=0 are x=-(3+sqrt(23))/2 ,x=(sqrt(23)-3)/2
Find the zeros of -2x^2-6x+7=0
The zeros of -2x^2-6x+7=0 are x=-(3+sqrt(23))/2 ,x=(sqrt(23)-3)/2