What are the solutions to the equation 24x+9=-16x^2 ?

The solutions to the equation 24x+9=-16x^2 are x=-3/4

Find the zeros of 24x+9=-16x^2

The zeros of 24x+9=-16x^2 are x=-3/4

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24 x + 9 = - 16 x^{2}

x = - \frac{3}{4}

Decimal Notation

x = - 0.75

Solution steps

24 x + 9 = - 16 x^{2}

Switch sides

- 16 x^{2} = 24 x + 9

Move

9

to the left side

- 16 x^{2} - 9 = 24 x

Move

24 x

to the left side

- 16 x^{2} - 9 - 24 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} - 24 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 16 ) ( - 9 )}{2 ( - 16 )}

(- 24)^{2} - 4 (- 16) (- 9) = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 ( - 16 )}

x = \frac{- ( - 24 )}{2 ( - 16 )}

\frac{- ( - 24 )}{2 ( - 16 )} = - \frac{3}{4}

x = - \frac{3}{4}

The solution to the quadratic equation is:

x = - \frac{3}{4}

(x - 7)^{2} - 7 (x - 7) + 10 = 0

5 x^{2} + 7 x + 20 = 7 x^{2} + 3 x - 10

- 2 x^{2} - 32 x - 112 = 0

3 x^{2} - 24 = - 9 x^{2}

5 x^{2} + 3 x - 14 = 0

What are the solutions to the equation 24x+9=-16x^2 ?
The solutions to the equation 24x+9=-16x^2 are x=-3/4
Find the zeros of 24x+9=-16x^2
The zeros of 24x+9=-16x^2 are x=-3/4