What are the solutions to the equation (x-7)^2-7(x-7)+10=0 ?

The solutions to the equation (x-7)^2-7(x-7)+10=0 are x=12,x=9

Find the zeros of (x-7)^2-7(x-7)+10=0

The zeros of (x-7)^2-7(x-7)+10=0 are x=12,x=9

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(x - 7)^{2} - 7 (x - 7) + 10 = 0

x = 12, x = 9

Solution steps

(x - 7)^{2} - 7 (x - 7) + 10 = 0

Expand

(x - 7)^{2} - 7 (x - 7) + 10 : x^{2} - 21 x + 108

x^{2} - 21 x + 108 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 1 \cdot 108}{2 \cdot 1}

(- 21)^{2} - 4 \cdot 1 \cdot 108 = 3

x_{1, 2} = \frac{- ( - 21 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 21 ) - 3}{2 \cdot 1}

x = \frac{- ( - 21 ) + 3}{2 \cdot 1} : 12

x = \frac{- ( - 21 ) - 3}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

x = 12, x = 9

5 x^{2} + 7 x + 20 = 7 x^{2} + 3 x - 10

- 2 x^{2} - 32 x - 112 = 0

3 x^{2} - 24 = - 9 x^{2}

5 x^{2} + 3 x - 14 = 0

(11 x - 1)^{2} - 4 (11 x - 1) - 5 = 0

What are the solutions to the equation (x-7)^2-7(x-7)+10=0 ?
The solutions to the equation (x-7)^2-7(x-7)+10=0 are x=12,x=9
Find the zeros of (x-7)^2-7(x-7)+10=0
The zeros of (x-7)^2-7(x-7)+10=0 are x=12,x=9