What are the solutions to the equation (x+9)(x+4)=-26 ?

The solutions to the equation (x+9)(x+4)=-26 are x=-13/2+i(sqrt(79))/2 ,x=-13/2-i(sqrt(79))/2

Find the zeros of (x+9)(x+4)=-26

The zeros of (x+9)(x+4)=-26 are x=-13/2+i(sqrt(79))/2 ,x=-13/2-i(sqrt(79))/2

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(x + 9) (x + 4) = - 26

x = - \frac{13}{2} + i \frac{79}{2}, x = - \frac{13}{2} - i \frac{79}{2}

Solution steps

(x + 9) (x + 4) = - 26

Expand

(x + 9) (x + 4) : x^{2} + 13 x + 36

x^{2} + 13 x + 36 = - 26

Move

26

to the left side

x^{2} + 13 x + 62 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 62}{2 \cdot 1}

Simplify

1 3^{2} - 4 \cdot 1 \cdot 62 : 79 i

x_{1, 2} = \frac{- 13 \pm 79 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 79 i}{2 \cdot 1}, x_{2} = \frac{- 13 - 79 i}{2 \cdot 1}

x = \frac{- 13 + 79 i}{2 \cdot 1} : - \frac{13}{2} + i \frac{79}{2}

x = \frac{- 13 - 79 i}{2 \cdot 1} : - \frac{13}{2} - i \frac{79}{2}

The solutions to the quadratic equation are:

x = - \frac{13}{2} + i \frac{79}{2}, x = - \frac{13}{2} - i \frac{79}{2}

9 y^{2} - y + 8 = 0

5 u^{2} - 19 u - 4 = 0

- 5 x^{2} + 7 x - 1 = 0

- x^{2} + 12 x - 6 = 0

x^{2} - 54 = - 5 x^{2}

What are the solutions to the equation (x+9)(x+4)=-26 ?
The solutions to the equation (x+9)(x+4)=-26 are x=-13/2+i(sqrt(79))/2 ,x=-13/2-i(sqrt(79))/2
Find the zeros of (x+9)(x+4)=-26
The zeros of (x+9)(x+4)=-26 are x=-13/2+i(sqrt(79))/2 ,x=-13/2-i(sqrt(79))/2