What are the solutions to the equation solvefor x,x^2+kx+6=0 ?

The solutions to the equation solvefor x,x^2+kx+6=0 are x=(-k+sqrt(k^2-24))/2 ,x=(-k-sqrt(k^2-24))/2

Find the zeros of solvefor x,x^2+kx+6=0

The zeros of solvefor x,x^2+kx+6=0 are x=(-k+sqrt(k^2-24))/2 ,x=(-k-sqrt(k^2-24))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x, x^{2} + k x + 6 = 0

x = \frac{- k + k ^{2} - 24}{2}, x = \frac{- k - k ^{2} - 24}{2}

Solution steps

x^{2} + k x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- k \pm k ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

k^{2} - 4 \cdot 1 \cdot 6 : k^{2} - 24

x_{1, 2} = \frac{- k \pm k ^{2} - 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- k + k ^{2} - 24}{2 \cdot 1}, x_{2} = \frac{- k - k ^{2} - 24}{2 \cdot 1}

x = \frac{- k + k ^{2} - 24}{2 \cdot 1} : \frac{- k + k ^{2} - 24}{2}

x = \frac{- k - k ^{2} - 24}{2 \cdot 1} : \frac{- k - k ^{2} - 24}{2}

The solutions to the quadratic equation are:

x = \frac{- k + k ^{2} - 24}{2}, x = \frac{- k - k ^{2} - 24}{2}

5 x^{2} + x - 10 = 0

\frac{x ^{2}}{4} + \frac{2 x}{3} = 0

11 x^{2} - 13 x = 0

8 + 2 x - 3 x^{2} = 0

x^{2} + 8 x = 884

What are the solutions to the equation solvefor x,x^2+kx+6=0 ?
The solutions to the equation solvefor x,x^2+kx+6=0 are x=(-k+sqrt(k^2-24))/2 ,x=(-k-sqrt(k^2-24))/2
Find the zeros of solvefor x,x^2+kx+6=0
The zeros of solvefor x,x^2+kx+6=0 are x=(-k+sqrt(k^2-24))/2 ,x=(-k-sqrt(k^2-24))/2