What are the solutions to the equation 8+2x-3x^2=0 ?

The solutions to the equation 8+2x-3x^2=0 are x=-4/3 ,x=2

Find the zeros of 8+2x-3x^2=0

The zeros of 8+2x-3x^2=0 are x=-4/3 ,x=2

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8 + 2 x - 3 x^{2} = 0

x = - \frac{4}{3}, x = 2

Solution steps

8 + 2 x - 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

2^{2} - 4 (- 3) \cdot 8 = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 ( - 3 )}, x_{2} = \frac{- 2 - 10}{2 ( - 3 )}

x = \frac{- 2 + 10}{2 ( - 3 )} : - \frac{4}{3}

x = \frac{- 2 - 10}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = 2

x^{2} + 8 x = 884

6 x^{2} + 5 = 30 + 2 x^{2}

x, y^{4} = x^{2} + 16

4 x^{2} - 32 x + 20 = 0

2 x^{2} + 16 x - 11

What are the solutions to the equation 8+2x-3x^2=0 ?
The solutions to the equation 8+2x-3x^2=0 are x=-4/3 ,x=2
Find the zeros of 8+2x-3x^2=0
The zeros of 8+2x-3x^2=0 are x=-4/3 ,x=2