What are the solutions to the equation (x^2)/4+(2x)/3 =0 ?

The solutions to the equation (x^2)/4+(2x)/3 =0 are x=0,x=-8/3

Find the zeros of (x^2)/4+(2x)/3 =0

The zeros of (x^2)/4+(2x)/3 =0 are x=0,x=-8/3

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\frac{x ^{2}}{4} + \frac{2 x}{3} = 0

x = 0, x = - \frac{8}{3}

Decimal

x = 0, x = - 2.66666 \dots

Solution steps

\frac{x ^{2}}{4} + \frac{2 x}{3} = 0

Find Least Common Multiplier of

4, 3 : 12

Multiply by LCM=

12

\frac{x ^{2}}{4} \cdot 12 + \frac{2 x}{3} \cdot 12 = 0 \cdot 12

Simplify

3 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

8^{2} - 4 \cdot 3 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 3}, x_{2} = \frac{- 8 - 8}{2 \cdot 3}

x = \frac{- 8 + 8}{2 \cdot 3} : 0

x = \frac{- 8 - 8}{2 \cdot 3} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{8}{3}

11 x^{2} - 13 x = 0

8 + 2 x - 3 x^{2} = 0

x^{2} + 8 x = 884

6 x^{2} + 5 = 30 + 2 x^{2}

x, y^{4} = x^{2} + 16

What are the solutions to the equation (x^2)/4+(2x)/3 =0 ?
The solutions to the equation (x^2)/4+(2x)/3 =0 are x=0,x=-8/3
Find the zeros of (x^2)/4+(2x)/3 =0
The zeros of (x^2)/4+(2x)/3 =0 are x=0,x=-8/3