What are the solutions to the equation factor 2x^2+4x+2=0 ?

The solutions to the equation factor 2x^2+4x+2=0 are x=-1

Find the zeros of factor 2x^2+4x+2=0

The zeros of factor 2x^2+4x+2=0 are x=-1

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2 x^{2} + 4 x + 2 = 0

x = - 1

Solution steps

2 x^{2} + 4 x + 2 = 0

Factor

2 x^{2} + 4 x + 2 : 2 (x + 1)^{2}

2 (x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0

Solve

x + 1 = 0 : x = - 1

The solution to the quadratic equation is:

x = - 1

49 x^{2} + 9 = 42 x

z^{2} + 11 z + 16 = 0

(x - \frac{1}{2})^{2} = 0

x^{2} + 3 k + 1 = (k + 2) x

x, (x^{5})^{2} = 7 y y^{5}

What are the solutions to the equation factor 2x^2+4x+2=0 ?
The solutions to the equation factor 2x^2+4x+2=0 are x=-1
Find the zeros of factor 2x^2+4x+2=0
The zeros of factor 2x^2+4x+2=0 are x=-1