What are the solutions to the equation 49x^2+9=42x ?

The solutions to the equation 49x^2+9=42x are x= 3/7

Find the zeros of 49x^2+9=42x

The zeros of 49x^2+9=42x are x= 3/7

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49 x^{2} + 9 = 42 x

x = \frac{3}{7}

Solution steps

49 x^{2} + 9 = 42 x

Move

42 x

to the left side

49 x^{2} + 9 - 42 x = 0

Write in the standard form

a x^{2} + b x + c = 0

49 x^{2} - 42 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 49 \cdot 9}{2 \cdot 49}

(- 42)^{2} - 4 \cdot 49 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 42 ) \pm 0}{2 \cdot 49}

x = \frac{- ( - 42 )}{2 \cdot 49}

\frac{- ( - 42 )}{2 \cdot 49} = \frac{3}{7}

x = \frac{3}{7}

The solution to the quadratic equation is:

x = \frac{3}{7}

z^{2} + 11 z + 16 = 0

(x - \frac{1}{2})^{2} = 0

x^{2} + 3 k + 1 = (k + 2) x

x, (x^{5})^{2} = 7 y y^{5}

4 x^{2} - 8 x = 12

What are the solutions to the equation 49x^2+9=42x ?
The solutions to the equation 49x^2+9=42x are x= 3/7
Find the zeros of 49x^2+9=42x
The zeros of 49x^2+9=42x are x= 3/7