What are the solutions to the equation x^2-x+5=55 ?

The solutions to the equation x^2-x+5=55 are x=(1+sqrt(201))/2 ,x=(1-sqrt(201))/2

Find the zeros of x^2-x+5=55

The zeros of x^2-x+5=55 are x=(1+sqrt(201))/2 ,x=(1-sqrt(201))/2

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x^{2} - x + 5 = 55

x = \frac{1 + 201}{2}, x = \frac{1 - 201}{2}

Solution steps

x^{2} - x + 5 = 55

Move

55

to the left side

x^{2} - x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 50 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 50) = 201

x_{1, 2} = \frac{- ( - 1 ) \pm 201}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 201}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 201}{2 \cdot 1}

x = \frac{- ( - 1 ) + 201}{2 \cdot 1} : \frac{1 + 201}{2}

x = \frac{- ( - 1 ) - 201}{2 \cdot 1} : \frac{1 - 201}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 201}{2}, x = \frac{1 - 201}{2}

2 c^{2} + 3 c + 2 = - 10

2 x^{2} - 16 x = - 24

4 w^{2} - 8 w - 5 = 0

3 x (x - 1) = 6

6 x^{2} - 24 = 30

What are the solutions to the equation x^2-x+5=55 ?
The solutions to the equation x^2-x+5=55 are x=(1+sqrt(201))/2 ,x=(1-sqrt(201))/2
Find the zeros of x^2-x+5=55
The zeros of x^2-x+5=55 are x=(1+sqrt(201))/2 ,x=(1-sqrt(201))/2