What are the solutions to the equation -6x^2+64x-222=-8x ?

The solutions to the equation -6x^2+64x-222=-8x are x=6-i,x=6+i

Find the zeros of -6x^2+64x-222=-8x

The zeros of -6x^2+64x-222=-8x are x=6-i,x=6+i

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- 6 x^{2} + 64 x - 222 = - 8 x

x = 6 - i, x = 6 + i

Solution steps

- 6 x^{2} + 64 x - 222 = - 8 x

Move

8 x

to the left side

- 6 x^{2} + 72 x - 222 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 ( - 6 ) ( - 222 )}{2 ( - 6 )}

Simplify

7 2^{2} - 4 (- 6) (- 222) : 12 i

x_{1, 2} = \frac{- 72 \pm 12 i}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 72 + 12 i}{2 ( - 6 )}, x_{2} = \frac{- 72 - 12 i}{2 ( - 6 )}

x = \frac{- 72 + 12 i}{2 ( - 6 )} : 6 - i

x = \frac{- 72 - 12 i}{2 ( - 6 )} : 6 + i

The solutions to the quadratic equation are:

x = 6 - i, x = 6 + i

12 x^{2} - 20 x + 3 = 0

- 2 x^{2} + 3 x + 3 = 0

5 (x + 3)^{2} = 2

x, y = 3 - x^{2}

V = π r^{2} h, r

What are the solutions to the equation -6x^2+64x-222=-8x ?
The solutions to the equation -6x^2+64x-222=-8x are x=6-i,x=6+i
Find the zeros of -6x^2+64x-222=-8x
The zeros of -6x^2+64x-222=-8x are x=6-i,x=6+i