What are the solutions to the equation 4(x-3)^2-27=-11 ?

The solutions to the equation 4(x-3)^2-27=-11 are x=5,x=1

Find the zeros of 4(x-3)^2-27=-11

The zeros of 4(x-3)^2-27=-11 are x=5,x=1

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4 (x - 3)^{2} - 27 = - 11

x = 5, x = 1

Solution steps

4 (x - 3)^{2} - 27 = - 11

Move

27

to the right side

4 (x - 3)^{2} = 16

Divide both sides by

4

(x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 4 : x = 5

Solve

x - 3 = - 4 : x = 1

The solutions to the quadratic equation are:

x = 5, x = 1

14 x^{2} - 4 x = 35 x - 10

n (n + 6) = 520

x^{2} = 255

(2 x - 1)^{2} + (3 x - 2)^{2} = 5

2 (x - 4)^{2} = 200

What are the solutions to the equation 4(x-3)^2-27=-11 ?
The solutions to the equation 4(x-3)^2-27=-11 are x=5,x=1
Find the zeros of 4(x-3)^2-27=-11
The zeros of 4(x-3)^2-27=-11 are x=5,x=1