What are the solutions to the equation 2x(3x-5)=x ?

The solutions to the equation 2x(3x-5)=x are x= 11/6 ,x=0

Find the zeros of 2x(3x-5)=x

The zeros of 2x(3x-5)=x are x= 11/6 ,x=0

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2 x (3 x - 5) = x

x = \frac{11}{6}, x = 0

Solution steps

2 x (3 x - 5) = x

Expand

2 x (3 x - 5) : 6 x^{2} - 10 x

6 x^{2} - 10 x = x

Move

x

to the left side

6 x^{2} - 11 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 11)^{2} - 4 \cdot 6 \cdot 0 = 11

x_{1, 2} = \frac{- ( - 11 ) \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 11}{2 \cdot 6}, x_{2} = \frac{- ( - 11 ) - 11}{2 \cdot 6}

x = \frac{- ( - 11 ) + 11}{2 \cdot 6} : \frac{11}{6}

x = \frac{- ( - 11 ) - 11}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

x = \frac{11}{6}, x = 0

(x - 4)^{2} (x + 2) = (x + 2)^{2} (x - 4)

x (x^{2} + 2 x + 3) = x^{3} - 1

2 x^{2} = - 9 x - 10

15 m (m + 5) = 38 m - 20

x^{2} + 2 4^{2} = 2 6^{2}

What are the solutions to the equation 2x(3x-5)=x ?
The solutions to the equation 2x(3x-5)=x are x= 11/6 ,x=0
Find the zeros of 2x(3x-5)=x
The zeros of 2x(3x-5)=x are x= 11/6 ,x=0