What are the solutions to the equation 15m(m+5)=38m-20 ?

The solutions to the equation 15m(m+5)=38m-20 are m=-4/5 ,m=-5/3

Find the zeros of 15m(m+5)=38m-20

The zeros of 15m(m+5)=38m-20 are m=-4/5 ,m=-5/3

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15 m (m + 5) = 38 m - 20

m = - \frac{4}{5}, m = - \frac{5}{3}

Decimal Notation

m = - 0.8, m = - 1.66666 \dots

Solution steps

15 m (m + 5) = 38 m - 20

Expand

15 m (m + 5) : 15 m^{2} + 75 m

15 m^{2} + 75 m = 38 m - 20

Move

20

to the left side

15 m^{2} + 75 m + 20 = 38 m

Move

38 m

to the left side

15 m^{2} + 37 m + 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 37 \pm 3 7 ^{2} - 4 \cdot 15 \cdot 20}{2 \cdot 15}

3 7^{2} - 4 \cdot 15 \cdot 20 = 13

m_{1, 2} = \frac{- 37 \pm 13}{2 \cdot 15}

Separate the solutions

m_{1} = \frac{- 37 + 13}{2 \cdot 15}, m_{2} = \frac{- 37 - 13}{2 \cdot 15}

m = \frac{- 37 + 13}{2 \cdot 15} : - \frac{4}{5}

m = \frac{- 37 - 13}{2 \cdot 15} : - \frac{5}{3}

The solutions to the quadratic equation are:

m = - \frac{4}{5}, m = - \frac{5}{3}

x^{2} + 2 4^{2} = 2 6^{2}

x^{2} - 4 x - 3 = 0

6 x^{2} + 450 = 0

x^{2} + 7 - 3 x = 1

(x - 2) (1 - 2 x) = 1

What are the solutions to the equation 15m(m+5)=38m-20 ?
The solutions to the equation 15m(m+5)=38m-20 are m=-4/5 ,m=-5/3
Find the zeros of 15m(m+5)=38m-20
The zeros of 15m(m+5)=38m-20 are m=-4/5 ,m=-5/3