What are the solutions to the equation x^2+7-3x=1 ?

The solutions to the equation x^2+7-3x=1 are x= 3/2+i(sqrt(15))/2 ,x= 3/2-i(sqrt(15))/2

Find the zeros of x^2+7-3x=1

The zeros of x^2+7-3x=1 are x= 3/2+i(sqrt(15))/2 ,x= 3/2-i(sqrt(15))/2

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x^{2} + 7 - 3 x = 1

x = \frac{3}{2} + i \frac{15}{2}, x = \frac{3}{2} - i \frac{15}{2}

Solution steps

x^{2} + 7 - 3 x = 1

Move

1

to the left side

x^{2} - 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 6 : 15 i

x_{1, 2} = \frac{- ( - 3 ) \pm 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 15 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 15 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 15 i}{2 \cdot 1} : \frac{3}{2} + i \frac{15}{2}

x = \frac{- ( - 3 ) - 15 i}{2 \cdot 1} : \frac{3}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{15}{2}, x = \frac{3}{2} - i \frac{15}{2}

(x - 2) (1 - 2 x) = 1

27 x^{2} + 18 x = 0

24 x^{2} - 2 x - 1 = 0

5 y^{2} + 30 = y^{2} + 6

2 x^{2} - 5 = 9

What are the solutions to the equation x^2+7-3x=1 ?
The solutions to the equation x^2+7-3x=1 are x= 3/2+i(sqrt(15))/2 ,x= 3/2-i(sqrt(15))/2
Find the zeros of x^2+7-3x=1
The zeros of x^2+7-3x=1 are x= 3/2+i(sqrt(15))/2 ,x= 3/2-i(sqrt(15))/2