What are the solutions to the equation completesquare x^2-4x-3=0 ?

The solutions to the equation completesquare x^2-4x-3=0 are x=sqrt(7)+2,x=-sqrt(7)+2

Find the zeros of completesquare x^2-4x-3=0

The zeros of completesquare x^2-4x-3=0 are x=sqrt(7)+2,x=-sqrt(7)+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 4 x - 3 = 0

x = 7 + 2, x = - 7 + 2

Solution steps

x^{2} - 4 x - 3 = 0

Move

3

to the right side

x^{2} - 4 x = 3

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = 7

For

the solutions are

f (x) = a, - a

Solve

x - 2 = 7 : x = 7 + 2

Solve

x - 2 = - 7 : x = - 7 + 2

The solutions to the quadratic equation are:

x = 7 + 2, x = - 7 + 2

6 x^{2} + 450 = 0

x^{2} + 7 - 3 x = 1

(x - 2) (1 - 2 x) = 1

27 x^{2} + 18 x = 0

24 x^{2} - 2 x - 1 = 0

What are the solutions to the equation completesquare x^2-4x-3=0 ?
The solutions to the equation completesquare x^2-4x-3=0 are x=sqrt(7)+2,x=-sqrt(7)+2
Find the zeros of completesquare x^2-4x-3=0
The zeros of completesquare x^2-4x-3=0 are x=sqrt(7)+2,x=-sqrt(7)+2