What are the solutions to the equation 27x^2+18x=0 ?

The solutions to the equation 27x^2+18x=0 are x=0,x=-2/3

Find the zeros of 27x^2+18x=0

The zeros of 27x^2+18x=0 are x=0,x=-2/3

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27 x^{2} + 18 x = 0

x = 0, x = - \frac{2}{3}

Solution steps

27 x^{2} + 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 27 \cdot 0}{2 \cdot 27}

1 8^{2} - 4 \cdot 27 \cdot 0 = 18

x_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 27}

Separate the solutions

x_{1} = \frac{- 18 + 18}{2 \cdot 27}, x_{2} = \frac{- 18 - 18}{2 \cdot 27}

x = \frac{- 18 + 18}{2 \cdot 27} : 0

x = \frac{- 18 - 18}{2 \cdot 27} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{2}{3}

24 x^{2} - 2 x - 1 = 0

5 y^{2} + 30 = y^{2} + 6

2 x^{2} - 5 = 9

2 x^{2} - 5 = 8

3 x^{2} + 6 x - 18 = 0

What are the solutions to the equation 27x^2+18x=0 ?
The solutions to the equation 27x^2+18x=0 are x=0,x=-2/3
Find the zeros of 27x^2+18x=0
The zeros of 27x^2+18x=0 are x=0,x=-2/3