What are the solutions to the equation 2x^2-5=9 ?

The solutions to the equation 2x^2-5=9 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 2x^2-5=9

The zeros of 2x^2-5=9 are x=sqrt(7),x=-sqrt(7)

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2 x^{2} - 5 = 9

x = 7, x = - 7

Solution steps

2 x^{2} - 5 = 9

Move

5

to the right side

2 x^{2} = 14

Divide both sides by

2

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

2 x^{2} - 5 = 8

3 x^{2} + 6 x - 18 = 0

3 x^{2} - 2 = 2 x - 1

(x - 4)^{2} = (3 - x) (1 + 2 x)

t, e = \frac{1}{2} a t^{2}

What are the solutions to the equation 2x^2-5=9 ?
The solutions to the equation 2x^2-5=9 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 2x^2-5=9
The zeros of 2x^2-5=9 are x=sqrt(7),x=-sqrt(7)