What are the solutions to the equation 6y^2+7y+2=0 ?

The solutions to the equation 6y^2+7y+2=0 are y=-1/2 ,y=-2/3

Find the zeros of 6y^2+7y+2=0

The zeros of 6y^2+7y+2=0 are y=-1/2 ,y=-2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 y^{2} + 7 y + 2 = 0

y = - \frac{1}{2}, y = - \frac{2}{3}

Solution steps

6 y^{2} + 7 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

7^{2} - 4 \cdot 6 \cdot 2 = 1

y_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- 7 + 1}{2 \cdot 6}, y_{2} = \frac{- 7 - 1}{2 \cdot 6}

y = \frac{- 7 + 1}{2 \cdot 6} : - \frac{1}{2}

y = \frac{- 7 - 1}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

y = - \frac{1}{2}, y = - \frac{2}{3}

4 (x - 2)^{2} - 1 = 0

(x + 8)^{2} = 9^{2}

x^{2} + 6 x = 71

8 x^{2} + 7 x = 2

x, f = x^{2} + 4 x + k

What are the solutions to the equation 6y^2+7y+2=0 ?
The solutions to the equation 6y^2+7y+2=0 are y=-1/2 ,y=-2/3
Find the zeros of 6y^2+7y+2=0
The zeros of 6y^2+7y+2=0 are y=-1/2 ,y=-2/3