What are the solutions to the equation x^2+6x=71 ?

The solutions to the equation x^2+6x=71 are x=-3+4sqrt(5),x=-3-4sqrt(5)

Find the zeros of x^2+6x=71

The zeros of x^2+6x=71 are x=-3+4sqrt(5),x=-3-4sqrt(5)

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x^{2} + 6 x = 71

x = - 3 + 45, x = - 3 - 45

Decimal Notation

x = 5.94427 \dots, x = - 11.94427 \dots

Solution steps

x^{2} + 6 x = 71

Move

71

to the left side

x^{2} + 6 x - 71 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 71 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 71) = 85

x_{1, 2} = \frac{- 6 \pm 8 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 8 5}{2 \cdot 1}, x_{2} = \frac{- 6 - 8 5}{2 \cdot 1}

x = \frac{- 6 + 8 5}{2 \cdot 1} : - 3 + 45

x = \frac{- 6 - 8 5}{2 \cdot 1} : - 3 - 45

The solutions to the quadratic equation are:

x = - 3 + 45, x = - 3 - 45

8 x^{2} + 7 x = 2

x, f = x^{2} + 4 x + k

20 x^{2} - 9 x = 20

(a + 5) x^{2} + (a + 3) x + 7 - 3 a = 0

x^{2} - 120 x + 3600 = 0

What are the solutions to the equation x^2+6x=71 ?
The solutions to the equation x^2+6x=71 are x=-3+4sqrt(5),x=-3-4sqrt(5)
Find the zeros of x^2+6x=71
The zeros of x^2+6x=71 are x=-3+4sqrt(5),x=-3-4sqrt(5)