What are the solutions to the equation 8x^2+7x=2 ?

The solutions to the equation 8x^2+7x=2 are x=(-7+sqrt(113))/(16),x=(-7-sqrt(113))/(16)

Find the zeros of 8x^2+7x=2

The zeros of 8x^2+7x=2 are x=(-7+sqrt(113))/(16),x=(-7-sqrt(113))/(16)

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8 x^{2} + 7 x = 2

x = \frac{- 7 + 113}{16}, x = \frac{- 7 - 113}{16}

Solution steps

8 x^{2} + 7 x = 2

Move

2

to the left side

8 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 8 ( - 2 )}{2 \cdot 8}

7^{2} - 4 \cdot 8 (- 2) = 113

x_{1, 2} = \frac{- 7 \pm 113}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 7 + 113}{2 \cdot 8}, x_{2} = \frac{- 7 - 113}{2 \cdot 8}

x = \frac{- 7 + 113}{2 \cdot 8} : \frac{- 7 + 113}{16}

x = \frac{- 7 - 113}{2 \cdot 8} : \frac{- 7 - 113}{16}

The solutions to the quadratic equation are:

x = \frac{- 7 + 113}{16}, x = \frac{- 7 - 113}{16}

x, f = x^{2} + 4 x + k

20 x^{2} - 9 x = 20

(a + 5) x^{2} + (a + 3) x + 7 - 3 a = 0

x^{2} - 120 x + 3600 = 0

x^{2} - 3 x = 2 x + 14

What are the solutions to the equation 8x^2+7x=2 ?
The solutions to the equation 8x^2+7x=2 are x=(-7+sqrt(113))/(16),x=(-7-sqrt(113))/(16)
Find the zeros of 8x^2+7x=2
The zeros of 8x^2+7x=2 are x=(-7+sqrt(113))/(16),x=(-7-sqrt(113))/(16)