What are the solutions to the equation 12x^2+25x=7 ?

The solutions to the equation 12x^2+25x=7 are x= 1/4 ,x=-7/3

Find the zeros of 12x^2+25x=7

The zeros of 12x^2+25x=7 are x= 1/4 ,x=-7/3

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12 x^{2} + 25 x = 7

x = \frac{1}{4}, x = - \frac{7}{3}

Solution steps

12 x^{2} + 25 x = 7

Move

7

to the left side

12 x^{2} + 25 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 12 ( - 7 )}{2 \cdot 12}

2 5^{2} - 4 \cdot 12 (- 7) = 31

x_{1, 2} = \frac{- 25 \pm 31}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 25 + 31}{2 \cdot 12}, x_{2} = \frac{- 25 - 31}{2 \cdot 12}

x = \frac{- 25 + 31}{2 \cdot 12} : \frac{1}{4}

x = \frac{- 25 - 31}{2 \cdot 12} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{7}{3}

2 x^{2} + 3 x - 1 = 3

(2 x + 1) (x + 7) = (x + 5) (3 x - 1)

\frac{2}{3} x^{2} + x + 3 = 0

(x - 8) (x - 10) = - 1

- 15 - 17 x + 4 x^{2} = 0

What are the solutions to the equation 12x^2+25x=7 ?
The solutions to the equation 12x^2+25x=7 are x= 1/4 ,x=-7/3
Find the zeros of 12x^2+25x=7
The zeros of 12x^2+25x=7 are x= 1/4 ,x=-7/3