What are the solutions to the equation -15-17x+4x^2=0 ?

The solutions to the equation -15-17x+4x^2=0 are x=5,x=-3/4

Find the zeros of -15-17x+4x^2=0

The zeros of -15-17x+4x^2=0 are x=5,x=-3/4

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- 15 - 17 x + 4 x^{2} = 0

x = 5, x = - \frac{3}{4}

Solution steps

- 15 - 17 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 17 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

(- 17)^{2} - 4 \cdot 4 (- 15) = 23

x_{1, 2} = \frac{- ( - 17 ) \pm 23}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 23}{2 \cdot 4}, x_{2} = \frac{- ( - 17 ) - 23}{2 \cdot 4}

x = \frac{- ( - 17 ) + 23}{2 \cdot 4} : 5

x = \frac{- ( - 17 ) - 23}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 5, x = - \frac{3}{4}

- x^{2} - 4 x + 10

2 x^{2} + 11 x + 19 = 0

(x - 4)^{2} + (x + 2)^{2} = 25

- 54 x^{2} - 36 x + 18 = 0

x^{2} = 9 \cdot 10

What are the solutions to the equation -15-17x+4x^2=0 ?
The solutions to the equation -15-17x+4x^2=0 are x=5,x=-3/4
Find the zeros of -15-17x+4x^2=0
The zeros of -15-17x+4x^2=0 are x=5,x=-3/4