What are the solutions to the equation (x-8)(x-10)=-1 ?

The solutions to the equation (x-8)(x-10)=-1 are x=9

Find the zeros of (x-8)(x-10)=-1

The zeros of (x-8)(x-10)=-1 are x=9

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(x - 8) (x - 10) = - 1

x = 9

Solution steps

(x - 8) (x - 10) = - 1

Expand

(x - 8) (x - 10) : x^{2} - 18 x + 80

x^{2} - 18 x + 80 = - 1

Move

1

to the left side

x^{2} - 18 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 81 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 18 )}{2 \cdot 1}

\frac{- ( - 18 )}{2 \cdot 1} = 9

x = 9

The solution to the quadratic equation is:

x = 9

- 15 - 17 x + 4 x^{2} = 0

- x^{2} - 4 x + 10

2 x^{2} + 11 x + 19 = 0

(x - 4)^{2} + (x + 2)^{2} = 25

- 54 x^{2} - 36 x + 18 = 0

What are the solutions to the equation (x-8)(x-10)=-1 ?
The solutions to the equation (x-8)(x-10)=-1 are x=9
Find the zeros of (x-8)(x-10)=-1
The zeros of (x-8)(x-10)=-1 are x=9