What are the solutions to the equation 2w^2+3w-1=0 ?

The solutions to the equation 2w^2+3w-1=0 are w=(-3+sqrt(17))/4 ,w=(-3-sqrt(17))/4

Find the zeros of 2w^2+3w-1=0

The zeros of 2w^2+3w-1=0 are w=(-3+sqrt(17))/4 ,w=(-3-sqrt(17))/4

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2 w^{2} + 3 w - 1 = 0

w = \frac{- 3 + 17}{4}, w = \frac{- 3 - 17}{4}

Decimal Notation

w = 0.28077 \dots, w = - 1.78077 \dots

Solution steps

2 w^{2} + 3 w - 1 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 1) = 17

w_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 3 + 17}{2 \cdot 2}, w_{2} = \frac{- 3 - 17}{2 \cdot 2}

w = \frac{- 3 + 17}{2 \cdot 2} : \frac{- 3 + 17}{4}

w = \frac{- 3 - 17}{2 \cdot 2} : \frac{- 3 - 17}{4}

The solutions to the quadratic equation are:

w = \frac{- 3 + 17}{4}, w = \frac{- 3 - 17}{4}

x^{2} - 0.9 x + 0.2 = 0

3 x^{2} = x - 5

x^{2} - 19 x + 6 = 0

(x - 2)^{2} - 49 = 0

3 x^{2} + 8 x = - 5

What are the solutions to the equation 2w^2+3w-1=0 ?
The solutions to the equation 2w^2+3w-1=0 are w=(-3+sqrt(17))/4 ,w=(-3-sqrt(17))/4
Find the zeros of 2w^2+3w-1=0
The zeros of 2w^2+3w-1=0 are w=(-3+sqrt(17))/4 ,w=(-3-sqrt(17))/4