What are the solutions to the equation x^2-0.9x+0.2=0 ?

The solutions to the equation x^2-0.9x+0.2=0 are x= 1/2 ,x= 2/5

Find the zeros of x^2-0.9x+0.2=0

The zeros of x^2-0.9x+0.2=0 are x= 1/2 ,x= 2/5

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x^{2} - 0.9 x + 0.2 = 0

x = \frac{1}{2}, x = \frac{2}{5}

Solution steps

x^{2} - 0.9 x + 0.2 = 0

Multiply both sides by

10

10 x^{2} - 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 10 \cdot 2}{2 \cdot 10}

(- 9)^{2} - 4 \cdot 10 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 10}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 10}

x = \frac{- ( - 9 ) + 1}{2 \cdot 10} : \frac{1}{2}

x = \frac{- ( - 9 ) - 1}{2 \cdot 10} : \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{2}{5}

3 x^{2} = x - 5

x^{2} - 19 x + 6 = 0

(x - 2)^{2} - 49 = 0

3 x^{2} + 8 x = - 5

(x - 1)^{2} = 3 - x

What are the solutions to the equation x^2-0.9x+0.2=0 ?
The solutions to the equation x^2-0.9x+0.2=0 are x= 1/2 ,x= 2/5
Find the zeros of x^2-0.9x+0.2=0
The zeros of x^2-0.9x+0.2=0 are x= 1/2 ,x= 2/5