What are the solutions to the equation 3x^2+8x=-5 ?

The solutions to the equation 3x^2+8x=-5 are x=-1,x=-5/3

Find the zeros of 3x^2+8x=-5

The zeros of 3x^2+8x=-5 are x=-1,x=-5/3

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3 x^{2} + 8 x = - 5

x = - 1, x = - \frac{5}{3}

Solution steps

3 x^{2} + 8 x = - 5

Move

5

to the left side

3 x^{2} + 8 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

8^{2} - 4 \cdot 3 \cdot 5 = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 \cdot 3}, x_{2} = \frac{- 8 - 2}{2 \cdot 3}

x = \frac{- 8 + 2}{2 \cdot 3} : - 1

x = \frac{- 8 - 2}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{5}{3}

(x - 1)^{2} = 3 - x

x^{2} - \frac{3}{2} x - 10 = 0

3 x^{2} - 5 x + 30 = 0

x = 2 x - x^{2}

2 x^{2} - 8 x + 12

What are the solutions to the equation 3x^2+8x=-5 ?
The solutions to the equation 3x^2+8x=-5 are x=-1,x=-5/3
Find the zeros of 3x^2+8x=-5
The zeros of 3x^2+8x=-5 are x=-1,x=-5/3