What are the solutions to the equation 3b^2=1 ?

The solutions to the equation 3b^2=1 are b= 1/(sqrt(3)),b=-1/(sqrt(3))

Find the zeros of 3b^2=1

The zeros of 3b^2=1 are b= 1/(sqrt(3)),b=-1/(sqrt(3))

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3 b^{2} = 1

b = \frac{1}{3}, b = - \frac{1}{3}

Solution steps

3 b^{2} = 1

Divide both sides by

3

b^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{1}{3}, b = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

b = \frac{1}{3}, b = - \frac{1}{3}

(2 x + 4)^{2} = 21

5 = - 0.04 t^{2} + 0.8 t + 10

x, z^{2} = 9 x^{2} + y^{2}

y, 3 y^{2} + 2 a y = - b

ab x^{2} + ab = a^{2} x + b^{2} x

What are the solutions to the equation 3b^2=1 ?
The solutions to the equation 3b^2=1 are b= 1/(sqrt(3)),b=-1/(sqrt(3))
Find the zeros of 3b^2=1
The zeros of 3b^2=1 are b= 1/(sqrt(3)),b=-1/(sqrt(3))