What are the solutions to the equation solvefor x,z^2=9x^2+y^2 ?

The solutions to the equation solvefor x,z^2=9x^2+y^2 are x=(sqrt(z^2-y^2))/3 ,x=-(sqrt(z^2-y^2))/3

Find the zeros of solvefor x,z^2=9x^2+y^2

The zeros of solvefor x,z^2=9x^2+y^2 are x=(sqrt(z^2-y^2))/3 ,x=-(sqrt(z^2-y^2))/3

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solve for

x, z^{2} = 9 x^{2} + y^{2}

x = \frac{z ^{2} - y ^{2}}{3}, x = - \frac{z ^{2} - y ^{2}}{3}

Solution steps

z^{2} = 9 x^{2} + y^{2}

Switch sides

9 x^{2} + y^{2} = z^{2}

Move

y^{2}

to the right side

9 x^{2} = z^{2} - y^{2}

Divide both sides by

9

x^{2} = \frac{z ^{2} - y ^{2}}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{z ^{2} - y ^{2}}{9}, x = - \frac{z ^{2} - y ^{2}}{9}

Simplify

\frac{z ^{2} - y ^{2}}{9} : \frac{z ^{2} - y ^{2}}{3}

Simplify

- \frac{z ^{2} - y ^{2}}{9} : - \frac{z ^{2} - y ^{2}}{3}

x = \frac{z ^{2} - y ^{2}}{3}, x = - \frac{z ^{2} - y ^{2}}{3}

y, 3 y^{2} + 2 a y = - b

ab x^{2} + ab = a^{2} x + b^{2} x

x^{2} + 6 x = - 8

12 x^{2} - 19 x + 5 = 0

0 = 0.25 x^{2} - x + 1

What are the solutions to the equation solvefor x,z^2=9x^2+y^2 ?
The solutions to the equation solvefor x,z^2=9x^2+y^2 are x=(sqrt(z^2-y^2))/3 ,x=-(sqrt(z^2-y^2))/3
Find the zeros of solvefor x,z^2=9x^2+y^2
The zeros of solvefor x,z^2=9x^2+y^2 are x=(sqrt(z^2-y^2))/3 ,x=-(sqrt(z^2-y^2))/3