What are the solutions to the equation 0=0.25x^2-x+1 ?

The solutions to the equation 0=0.25x^2-x+1 are x=2

Find the zeros of 0=0.25x^2-x+1

The zeros of 0=0.25x^2-x+1 are x=2

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0 = 0.25 x^{2} - x + 1

x = 2

Solution steps

0 = 0.25 x^{2} - x + 1

Multiply both sides by

100

0 = 25 x^{2} - 100 x + 100

Switch sides

25 x^{2} - 100 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 100 ) \pm ( - 100 ) ^{2} - 4 \cdot 25 \cdot 100}{2 \cdot 25}

(- 100)^{2} - 4 \cdot 25 \cdot 100 = 0

x_{1, 2} = \frac{- ( - 100 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 100 )}{2 \cdot 25}

\frac{- ( - 100 )}{2 \cdot 25} = 2

x = 2

The solution to the quadratic equation is:

x = 2

(13.5 + 0.75 x) \cdot x = - 24

- 3 x^{2} - 54 x + 51 = 0

5 x^{2} - 40 x - 100 = 0

17 t^{2} - 48 t + 28 = 0

(2 a + 2) (a) = 60

What are the solutions to the equation 0=0.25x^2-x+1 ?
The solutions to the equation 0=0.25x^2-x+1 are x=2
Find the zeros of 0=0.25x^2-x+1
The zeros of 0=0.25x^2-x+1 are x=2