What are the solutions to the equation 12x^2-19x+5=0 ?

The solutions to the equation 12x^2-19x+5=0 are x= 5/4 ,x= 1/3

Find the zeros of 12x^2-19x+5=0

The zeros of 12x^2-19x+5=0 are x= 5/4 ,x= 1/3

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12 x^{2} - 19 x + 5 = 0

x = \frac{5}{4}, x = \frac{1}{3}

Decimal Notation

x = 1.25, x = 0.33333 \dots

Solution steps

12 x^{2} - 19 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 12 \cdot 5}{2 \cdot 12}

(- 19)^{2} - 4 \cdot 12 \cdot 5 = 11

x_{1, 2} = \frac{- ( - 19 ) \pm 11}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 11}{2 \cdot 12}, x_{2} = \frac{- ( - 19 ) - 11}{2 \cdot 12}

x = \frac{- ( - 19 ) + 11}{2 \cdot 12} : \frac{5}{4}

x = \frac{- ( - 19 ) - 11}{2 \cdot 12} : \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = \frac{1}{3}

0 = 0.25 x^{2} - x + 1

(13.5 + 0.75 x) \cdot x = - 24

- 3 x^{2} - 54 x + 51 = 0

5 x^{2} - 40 x - 100 = 0

17 t^{2} - 48 t + 28 = 0

What are the solutions to the equation 12x^2-19x+5=0 ?
The solutions to the equation 12x^2-19x+5=0 are x= 5/4 ,x= 1/3
Find the zeros of 12x^2-19x+5=0
The zeros of 12x^2-19x+5=0 are x= 5/4 ,x= 1/3