What are the solutions to the equation -3x^2-54x+51=0 ?

The solutions to the equation -3x^2-54x+51=0 are x=-9-7sqrt(2),x=7sqrt(2)-9

Find the zeros of -3x^2-54x+51=0

The zeros of -3x^2-54x+51=0 are x=-9-7sqrt(2),x=7sqrt(2)-9

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- 3 x^{2} - 54 x + 51 = 0

x = - 9 - 72, x = 72 - 9

Decimal Notation

x = - 18.89949 \dots, x = 0.89949 \dots

Solution steps

- 3 x^{2} - 54 x + 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 ( - 3 ) \cdot 51}{2 ( - 3 )}

(- 54)^{2} - 4 (- 3) \cdot 51 = 422

x_{1, 2} = \frac{- ( - 54 ) \pm 42 2}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 54 ) + 42 2}{2 ( - 3 )}, x_{2} = \frac{- ( - 54 ) - 42 2}{2 ( - 3 )}

x = \frac{- ( - 54 ) + 42 2}{2 ( - 3 )} : - 9 - 72

x = \frac{- ( - 54 ) - 42 2}{2 ( - 3 )} : 72 - 9

The solutions to the quadratic equation are:

x = - 9 - 72, x = 72 - 9

5 x^{2} - 40 x - 100 = 0

17 t^{2} - 48 t + 28 = 0

(2 a + 2) (a) = 60

9 p + 5 p^{2} - 15 = p^{2} + 5 p

3 (x - 7)^{2} = 30

What are the solutions to the equation -3x^2-54x+51=0 ?
The solutions to the equation -3x^2-54x+51=0 are x=-9-7sqrt(2),x=7sqrt(2)-9
Find the zeros of -3x^2-54x+51=0
The zeros of -3x^2-54x+51=0 are x=-9-7sqrt(2),x=7sqrt(2)-9