What are the solutions to the equation (2a+2)(a)=60 ?

The solutions to the equation (2a+2)(a)=60 are a=5,a=-6

Find the zeros of (2a+2)(a)=60

The zeros of (2a+2)(a)=60 are a=5,a=-6

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(2 a + 2) (a) = 60

a = 5, a = - 6

Solution steps

(2 a + 2) (a) = 60

Expand

(2 a + 2) (a) : 2 a^{2} + 2 a

2 a^{2} + 2 a = 60

Move

60

to the left side

2 a^{2} + 2 a - 60 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 60) = 22

a_{1, 2} = \frac{- 2 \pm 22}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 2 + 22}{2 \cdot 2}, a_{2} = \frac{- 2 - 22}{2 \cdot 2}

a = \frac{- 2 + 22}{2 \cdot 2} : 5

a = \frac{- 2 - 22}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

a = 5, a = - 6

9 p + 5 p^{2} - 15 = p^{2} + 5 p

3 (x - 7)^{2} = 30

- 4 x^{2} = 3 x^{2} - 4

3 x^{2} - 4 = 5 x

x^{2} - 5 = 13 - x^{2}

What are the solutions to the equation (2a+2)(a)=60 ?
The solutions to the equation (2a+2)(a)=60 are a=5,a=-6
Find the zeros of (2a+2)(a)=60
The zeros of (2a+2)(a)=60 are a=5,a=-6