What are the solutions to the equation 9p+5p^2-15=p^2+5p ?

The solutions to the equation 9p+5p^2-15=p^2+5p are p= 3/2 ,p=-5/2

Find the zeros of 9p+5p^2-15=p^2+5p

The zeros of 9p+5p^2-15=p^2+5p are p= 3/2 ,p=-5/2

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9 p + 5 p^{2} - 15 = p^{2} + 5 p

p = \frac{3}{2}, p = - \frac{5}{2}

Decimal Notation

p = 1.5, p = - 2.5

Solution steps

9 p + 5 p^{2} - 15 = p^{2} + 5 p

Move

5 p

to the left side

5 p^{2} + 4 p - 15 = p^{2}

Move

p^{2}

to the left side

4 p^{2} + 4 p - 15 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 15) = 16

p_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- 4 + 16}{2 \cdot 4}, p_{2} = \frac{- 4 - 16}{2 \cdot 4}

p = \frac{- 4 + 16}{2 \cdot 4} : \frac{3}{2}

p = \frac{- 4 - 16}{2 \cdot 4} : - \frac{5}{2}

The solutions to the quadratic equation are:

p = \frac{3}{2}, p = - \frac{5}{2}

3 (x - 7)^{2} = 30

- 4 x^{2} = 3 x^{2} - 4

3 x^{2} - 4 = 5 x

x^{2} - 5 = 13 - x^{2}

x, x^{2} + y^{2} - 10 x + 9 = 0

What are the solutions to the equation 9p+5p^2-15=p^2+5p ?
The solutions to the equation 9p+5p^2-15=p^2+5p are p= 3/2 ,p=-5/2
Find the zeros of 9p+5p^2-15=p^2+5p
The zeros of 9p+5p^2-15=p^2+5p are p= 3/2 ,p=-5/2