What are the solutions to the equation -4x^2=3x^2-4 ?

The solutions to the equation -4x^2=3x^2-4 are x= 2/(sqrt(7)),x=-2/(sqrt(7))

Find the zeros of -4x^2=3x^2-4

The zeros of -4x^2=3x^2-4 are x= 2/(sqrt(7)),x=-2/(sqrt(7))

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- 4 x^{2} = 3 x^{2} - 4

x = \frac{2}{7}, x = - \frac{2}{7}

Decimal Notation

x = 0.75592 \dots, x = - 0.75592 \dots

Solution steps

- 4 x^{2} = 3 x^{2} - 4

Move

3 x^{2}

to the left side

- 7 x^{2} = - 4

Divide both sides by

- 7

x^{2} = \frac{4}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{7}, x = - \frac{4}{7}

\frac{4}{7} = \frac{2}{7}

- \frac{4}{7} = - \frac{2}{7}

x = \frac{2}{7}, x = - \frac{2}{7}

3 x^{2} - 4 = 5 x

x^{2} - 5 = 13 - x^{2}

x, x^{2} + y^{2} - 10 x + 9 = 0

25 x^{2} - 10 x = 0

x (2 x - 7) = 4 (x - 3)

What are the solutions to the equation -4x^2=3x^2-4 ?
The solutions to the equation -4x^2=3x^2-4 are x= 2/(sqrt(7)),x=-2/(sqrt(7))
Find the zeros of -4x^2=3x^2-4
The zeros of -4x^2=3x^2-4 are x= 2/(sqrt(7)),x=-2/(sqrt(7))