What are the solutions to the equation (2w+1)w=66 ?

The solutions to the equation (2w+1)w=66 are w= 11/2 ,w=-6

Find the zeros of (2w+1)w=66

The zeros of (2w+1)w=66 are w= 11/2 ,w=-6

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(2 w + 1) w = 66

w = \frac{11}{2}, w = - 6

Solution steps

(2 w + 1) w = 66

Expand

(2 w + 1) w : 2 w^{2} + w

2 w^{2} + w = 66

Move

66

to the left side

2 w^{2} + w - 66 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 66 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 66) = 23

w_{1, 2} = \frac{- 1 \pm 23}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 1 + 23}{2 \cdot 2}, w_{2} = \frac{- 1 - 23}{2 \cdot 2}

w = \frac{- 1 + 23}{2 \cdot 2} : \frac{11}{2}

w = \frac{- 1 - 23}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

w = \frac{11}{2}, w = - 6

a, x = a^{2} + b^{2} + c^{3}

x^{2} - 3 x = 7 x^{2} + 5 x

2 x (x - 5) = - 3 x - 3

(x - 6) (x + 2) + x^{2} + 4 = (x - 4) (x - 1)

x^{2} - 8 x + 12 = 0

What are the solutions to the equation (2w+1)w=66 ?
The solutions to the equation (2w+1)w=66 are w= 11/2 ,w=-6
Find the zeros of (2w+1)w=66
The zeros of (2w+1)w=66 are w= 11/2 ,w=-6