What are the solutions to the equation 3x^2-4x+7x-18=2x^2 ?

The solutions to the equation 3x^2-4x+7x-18=2x^2 are x=3,x=-6

Find the zeros of 3x^2-4x+7x-18=2x^2

The zeros of 3x^2-4x+7x-18=2x^2 are x=3,x=-6

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3 x^{2} - 4 x + 7 x - 18 = 2 x^{2}

x = 3, x = - 6

Solution steps

3 x^{2} - 4 x + 7 x - 18 = 2 x^{2}

Refine

3 x^{2} + 3 x - 18 = 2 x^{2}

Move

2 x^{2}

to the left side

x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 1}, x_{2} = \frac{- 3 - 9}{2 \cdot 1}

x = \frac{- 3 + 9}{2 \cdot 1} : 3

x = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

x^{2} + 4 x - 12 = 0

x (x - 10) + 24 = 0

16.1 t^{2} + 200 t - 200 = 0

x^{2} - 19 x + 102 = - x - 6

5 x^{2} + 5 x - 5 = 0

What are the solutions to the equation 3x^2-4x+7x-18=2x^2 ?
The solutions to the equation 3x^2-4x+7x-18=2x^2 are x=3,x=-6
Find the zeros of 3x^2-4x+7x-18=2x^2
The zeros of 3x^2-4x+7x-18=2x^2 are x=3,x=-6