What are the solutions to the equation x^2-12x-62=0 ?

The solutions to the equation x^2-12x-62=0 are x=6+7sqrt(2),x=6-7sqrt(2)

Find the zeros of x^2-12x-62=0

The zeros of x^2-12x-62=0 are x=6+7sqrt(2),x=6-7sqrt(2)

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x^{2} - 12 x - 62 = 0

x = 6 + 72, x = 6 - 72

Solution steps

x^{2} - 12 x - 62 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 62 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 62) = 142

x_{1, 2} = \frac{- ( - 12 ) \pm 14 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 14 2}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 14 2}{2 \cdot 1}

x = \frac{- ( - 12 ) + 14 2}{2 \cdot 1} : 6 + 72

x = \frac{- ( - 12 ) - 14 2}{2 \cdot 1} : 6 - 72

The solutions to the quadratic equation are:

x = 6 + 72, x = 6 - 72

y + 3 y^{2} = 24

5 v^{2} + 15 v + 8 = 0

64 x^{2} + 25 = 0

y, y^{2} + 7 b^{2} = 8 b y

x^{2} + 10 x + 25 = 0

What are the solutions to the equation x^2-12x-62=0 ?
The solutions to the equation x^2-12x-62=0 are x=6+7sqrt(2),x=6-7sqrt(2)
Find the zeros of x^2-12x-62=0
The zeros of x^2-12x-62=0 are x=6+7sqrt(2),x=6-7sqrt(2)