What are the solutions to the equation m=n-(ax^2)/2 ?

The solutions to the equation m=n-(ax^2)/2 are x=isqrt((2m-2n)/a),x=-isqrt((2m-2n)/a);\quad a\ne 0

Find the zeros of m=n-(ax^2)/2

The zeros of m=n-(ax^2)/2 are x=isqrt((2m-2n)/a),x=-isqrt((2m-2n)/a);\quad a\ne 0

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m = n - \frac{a x ^{2}}{2}

x = i \frac{2 m - 2 n}{a}, x = - i \frac{2 m - 2 n}{a}; a \neq = 0

Solution steps

m = n - \frac{a x ^{2}}{2}

Switch sides

n - \frac{a x ^{2}}{2} = m

Move

n

to the right side

- \frac{a x ^{2}}{2} = m - n

Multiply both sides by

2

- a x^{2} = 2 m - 2 n

Divide both sides by

- a; a \neq = 0

x^{2} = - \frac{2 m - 2 n}{a}; a \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2 m - 2 n}{a}, x = - - \frac{2 m - 2 n}{a}; a \neq = 0

Simplify

- \frac{2 m - 2 n}{a} : i \frac{2 m - 2 n}{a}

Simplify

- - \frac{2 m - 2 n}{a} : - i \frac{2 m - 2 n}{a}

x = i \frac{2 m - 2 n}{a}, x = - i \frac{2 m - 2 n}{a}; a \neq = 0

x^{2} - 12 x - 62 = 0

y + 3 y^{2} = 24

5 v^{2} + 15 v + 8 = 0

64 x^{2} + 25 = 0

y, y^{2} + 7 b^{2} = 8 b y

What are the solutions to the equation m=n-(ax^2)/2 ?
The solutions to the equation m=n-(ax^2)/2 are x=isqrt((2m-2n)/a),x=-isqrt((2m-2n)/a);\quad a\ne 0
Find the zeros of m=n-(ax^2)/2
The zeros of m=n-(ax^2)/2 are x=isqrt((2m-2n)/a),x=-isqrt((2m-2n)/a);\quad a\ne 0