What are the solutions to the equation 64x^2+25=0 ?

The solutions to the equation 64x^2+25=0 are x= 5/8 i,x=-5/8 i

Find the zeros of 64x^2+25=0

The zeros of 64x^2+25=0 are x= 5/8 i,x=-5/8 i

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64 x^{2} + 25 = 0

x = \frac{5}{8} i, x = - \frac{5}{8} i

Solution steps

64 x^{2} + 25 = 0

Move

25

to the right side

64 x^{2} = - 25

Divide both sides by

64

x^{2} = - \frac{25}{64}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{25}{64}, x = - - \frac{25}{64}

- \frac{25}{64} = \frac{5}{8} i

- - \frac{25}{64} = - \frac{5}{8} i

x = \frac{5}{8} i, x = - \frac{5}{8} i

y, y^{2} + 7 b^{2} = 8 b y

x^{2} + 10 x + 25 = 0

- 3 x^{2} - 16 x + 7 = 4

- 2 x^{2} - 8 x - 22 = 0

y^{2} + 10 y + 8 = 0

What are the solutions to the equation 64x^2+25=0 ?
The solutions to the equation 64x^2+25=0 are x= 5/8 i,x=-5/8 i
Find the zeros of 64x^2+25=0
The zeros of 64x^2+25=0 are x= 5/8 i,x=-5/8 i