What are the solutions to the equation y+3y^2=24 ?

The solutions to the equation y+3y^2=24 are y= 8/3 ,y=-3

Find the zeros of y+3y^2=24

The zeros of y+3y^2=24 are y= 8/3 ,y=-3

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y + 3 y^{2} = 24

y = \frac{8}{3}, y = - 3

Solution steps

y + 3 y^{2} = 24

Move

24

to the left side

y + 3 y^{2} - 24 = 0

Write in the standard form

a x^{2} + b x + c = 0

3 y^{2} + y - 24 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 24 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 24) = 17

y_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 1 + 17}{2 \cdot 3}, y_{2} = \frac{- 1 - 17}{2 \cdot 3}

y = \frac{- 1 + 17}{2 \cdot 3} : \frac{8}{3}

y = \frac{- 1 - 17}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

y = \frac{8}{3}, y = - 3

5 v^{2} + 15 v + 8 = 0

64 x^{2} + 25 = 0

y, y^{2} + 7 b^{2} = 8 b y

x^{2} + 10 x + 25 = 0

- 3 x^{2} - 16 x + 7 = 4

What are the solutions to the equation y+3y^2=24 ?
The solutions to the equation y+3y^2=24 are y= 8/3 ,y=-3
Find the zeros of y+3y^2=24
The zeros of y+3y^2=24 are y= 8/3 ,y=-3