What are the solutions to the equation -3x^2-16x+7=4 ?

The solutions to the equation -3x^2-16x+7=4 are x=-(8+sqrt(73))/3 ,x=(sqrt(73)-8)/3

Find the zeros of -3x^2-16x+7=4

The zeros of -3x^2-16x+7=4 are x=-(8+sqrt(73))/3 ,x=(sqrt(73)-8)/3

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- 3 x^{2} - 16 x + 7 = 4

x = - \frac{8 + 73}{3}, x = \frac{73 - 8}{3}

Solution steps

- 3 x^{2} - 16 x + 7 = 4

Move

4

to the left side

- 3 x^{2} - 16 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 3 ) \cdot 3}{2 ( - 3 )}

(- 16)^{2} - 4 (- 3) \cdot 3 = 273

x_{1, 2} = \frac{- ( - 16 ) \pm 2 73}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 73}{2 ( - 3 )}, x_{2} = \frac{- ( - 16 ) - 2 73}{2 ( - 3 )}

x = \frac{- ( - 16 ) + 2 73}{2 ( - 3 )} : - \frac{8 + 73}{3}

x = \frac{- ( - 16 ) - 2 73}{2 ( - 3 )} : \frac{73 - 8}{3}

The solutions to the quadratic equation are:

x = - \frac{8 + 73}{3}, x = \frac{73 - 8}{3}

- 2 x^{2} - 8 x - 22 = 0

y^{2} + 10 y + 8 = 0

x^{2} - 5 = - 5

10 k^{2} + 9 k - 1 = 6 k^{2}

(2 y + 7)^{2} = 49

What are the solutions to the equation -3x^2-16x+7=4 ?
The solutions to the equation -3x^2-16x+7=4 are x=-(8+sqrt(73))/3 ,x=(sqrt(73)-8)/3
Find the zeros of -3x^2-16x+7=4
The zeros of -3x^2-16x+7=4 are x=-(8+sqrt(73))/3 ,x=(sqrt(73)-8)/3