What are the solutions to the equation -2x^2-8x-22=0 ?

The solutions to the equation -2x^2-8x-22=0 are x=-2-sqrt(7)i,x=-2+sqrt(7)i

Find the zeros of -2x^2-8x-22=0

The zeros of -2x^2-8x-22=0 are x=-2-sqrt(7)i,x=-2+sqrt(7)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 8 x - 22 = 0

x = - 2 - 7 i, x = - 2 + 7 i

Solution steps

- 2 x^{2} - 8 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 2 ) ( - 22 )}{2 ( - 2 )}

Simplify

(- 8)^{2} - 4 (- 2) (- 22) : 47 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 7 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 7 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 8 ) - 4 7 i}{2 ( - 2 )}

x = \frac{- ( - 8 ) + 4 7 i}{2 ( - 2 )} : - 2 - 7 i

x = \frac{- ( - 8 ) - 4 7 i}{2 ( - 2 )} : - 2 + 7 i

The solutions to the quadratic equation are:

x = - 2 - 7 i, x = - 2 + 7 i

y^{2} + 10 y + 8 = 0

x^{2} - 5 = - 5

10 k^{2} + 9 k - 1 = 6 k^{2}

(2 y + 7)^{2} = 49

2 x^{2} = 12 - 5 x

What are the solutions to the equation -2x^2-8x-22=0 ?
The solutions to the equation -2x^2-8x-22=0 are x=-2-sqrt(7)i,x=-2+sqrt(7)i
Find the zeros of -2x^2-8x-22=0
The zeros of -2x^2-8x-22=0 are x=-2-sqrt(7)i,x=-2+sqrt(7)i