What are the solutions to the equation 10k^2+9k-1=6k^2 ?

The solutions to the equation 10k^2+9k-1=6k^2 are k=(-9+sqrt(97))/8 ,k=(-9-sqrt(97))/8

Find the zeros of 10k^2+9k-1=6k^2

The zeros of 10k^2+9k-1=6k^2 are k=(-9+sqrt(97))/8 ,k=(-9-sqrt(97))/8

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10 k^{2} + 9 k - 1 = 6 k^{2}

k = \frac{- 9 + 97}{8}, k = \frac{- 9 - 97}{8}

Decimal Notation

k = 0.10610 \dots, k = - 2.35610 \dots

Solution steps

10 k^{2} + 9 k - 1 = 6 k^{2}

Move

6 k^{2}

to the left side

4 k^{2} + 9 k - 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

9^{2} - 4 \cdot 4 (- 1) = 97

k_{1, 2} = \frac{- 9 \pm 97}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- 9 + 97}{2 \cdot 4}, k_{2} = \frac{- 9 - 97}{2 \cdot 4}

k = \frac{- 9 + 97}{2 \cdot 4} : \frac{- 9 + 97}{8}

k = \frac{- 9 - 97}{2 \cdot 4} : \frac{- 9 - 97}{8}

The solutions to the quadratic equation are:

k = \frac{- 9 + 97}{8}, k = \frac{- 9 - 97}{8}

(2 y + 7)^{2} = 49

2 x^{2} = 12 - 5 x

t^{2} - 8 t + 14 = 0

x^{2} - 18 x + 81 = 12

- x^{2} - 3 x + 9 = - 9 + 6 x - 2 x^{2}

What are the solutions to the equation 10k^2+9k-1=6k^2 ?
The solutions to the equation 10k^2+9k-1=6k^2 are k=(-9+sqrt(97))/8 ,k=(-9-sqrt(97))/8
Find the zeros of 10k^2+9k-1=6k^2
The zeros of 10k^2+9k-1=6k^2 are k=(-9+sqrt(97))/8 ,k=(-9-sqrt(97))/8