What are the solutions to the equation (2y+7)^2=49 ?

The solutions to the equation (2y+7)^2=49 are y=0,y=-7

Find the zeros of (2y+7)^2=49

The zeros of (2y+7)^2=49 are y=0,y=-7

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(2 y + 7)^{2} = 49

y = 0, y = - 7

Solution steps

(2 y + 7)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 y + 7 = 49 : y = 0

Solve

2 y + 7 = - 49 : y = - 7

The solutions to the quadratic equation are:

y = 0, y = - 7

2 x^{2} = 12 - 5 x

t^{2} - 8 t + 14 = 0

x^{2} - 18 x + 81 = 12

- x^{2} - 3 x + 9 = - 9 + 6 x - 2 x^{2}

x^{2} - (k - 3) x - 6 = 0

What are the solutions to the equation (2y+7)^2=49 ?
The solutions to the equation (2y+7)^2=49 are y=0,y=-7
Find the zeros of (2y+7)^2=49
The zeros of (2y+7)^2=49 are y=0,y=-7