What are the solutions to the equation 10+x(x-2)=2 ?

The solutions to the equation 10+x(x-2)=2 are x=1+sqrt(7)i,x=1-sqrt(7)i

Find the zeros of 10+x(x-2)=2

The zeros of 10+x(x-2)=2 are x=1+sqrt(7)i,x=1-sqrt(7)i

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10 + x (x - 2) = 2

x = 1 + 7 i, x = 1 - 7 i

Solution steps

10 + x (x - 2) = 2

Expand

10 + x (x - 2) : 10 + x^{2} - 2 x

10 + x^{2} - 2 x = 2

Move

2

to the left side

x^{2} - 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 8 : 27 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 7 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 7 i}{2 \cdot 1} : 1 + 7 i

x = \frac{- ( - 2 ) - 2 7 i}{2 \cdot 1} : 1 - 7 i

The solutions to the quadratic equation are:

x = 1 + 7 i, x = 1 - 7 i

8 v^{2} + 8 = - 32

17 x^{2} + 719 x = 0

y, x = y^{2} - 1

6 n^{2} + 4 n - 1 = 0

k^{2} - 2 k - 3 = 0

What are the solutions to the equation 10+x(x-2)=2 ?
The solutions to the equation 10+x(x-2)=2 are x=1+sqrt(7)i,x=1-sqrt(7)i
Find the zeros of 10+x(x-2)=2
The zeros of 10+x(x-2)=2 are x=1+sqrt(7)i,x=1-sqrt(7)i