What are the solutions to the equation z^2-3z-7=0 ?

The solutions to the equation z^2-3z-7=0 are z=(3+sqrt(37))/2 ,z=(3-sqrt(37))/2

Find the zeros of z^2-3z-7=0

The zeros of z^2-3z-7=0 are z=(3+sqrt(37))/2 ,z=(3-sqrt(37))/2

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z^{2} - 3 z - 7 = 0

z = \frac{3 + 37}{2}, z = \frac{3 - 37}{2}

Solution steps

z^{2} - 3 z - 7 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 7) = 37

z_{1, 2} = \frac{- ( - 3 ) \pm 37}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 3 ) + 37}{2 \cdot 1}, z_{2} = \frac{- ( - 3 ) - 37}{2 \cdot 1}

z = \frac{- ( - 3 ) + 37}{2 \cdot 1} : \frac{3 + 37}{2}

z = \frac{- ( - 3 ) - 37}{2 \cdot 1} : \frac{3 - 37}{2}

The solutions to the quadratic equation are:

z = \frac{3 + 37}{2}, z = \frac{3 - 37}{2}

(x - 4)^{2} - 9 = x

- 25 x^{2} + 144 = 0

t^{2} - 6 t - 1 = 0

- 16 x^{2} + 40 x + 62 = 0

4 x^{2} + (n - 6) x - 36 = 0

What are the solutions to the equation z^2-3z-7=0 ?
The solutions to the equation z^2-3z-7=0 are z=(3+sqrt(37))/2 ,z=(3-sqrt(37))/2
Find the zeros of z^2-3z-7=0
The zeros of z^2-3z-7=0 are z=(3+sqrt(37))/2 ,z=(3-sqrt(37))/2